A function is defined as follows:f(x)=\{\table-x/\sqrtx^2\text{,},x\neq0;0\text{,},x=0 Which one of the following is correct in respect [NDA II 2017]

Correct Answer is : f(x) is discontinuous at x=0

f(x) is continuous at x=0 but not differentiable at x=0

f(x) is continuous as well as differentiable atx=0

UPSC NDA 2 2017 Mathematics Solved Paper

Question : 62 of 120

Marks: +1, -0

A function is defined as follows:f(x)={

−

√x2

x≠0

x=0

Which one of the following is correct in respect

[NDA II 2017]

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