UPSC NDA 2 2017 Mathematics Solved Paper

© examsiri.com

Question : 58 of 120

Marks: +1, -0

The equation of the circle which passes through the points (1,0),(0,−6), and (3,4) is

[NDA II 2017]

4x2+4y2+142x+47y+140=0
4x2+4y2−142x+47y+138=0
4x2+4y2−142x+47y+138=0
4x2+4y2+150x−49y+138=0

Go to Question:

Prev Question

Next Question