UPSC NDA 2 2017 Mathematics Solved Paper

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Question : 48 of 120

Marks: +1, -0

For any vector

→

a

|

→

a

×

⋀

x

|2+|

→

a

×

⋀

j

|2+|

→

a

×

⋀

k

|2

is equal to

[NDA II 2017]

|
→
a
|2
2|
→
a
|2
3|
→
a
|2
4|
→
a
|2

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