If \sin18^{0}= \frac\sqrt{5}-1}{4}, then what is the value of \sin81^\circ [NDA II 2016]

Correct Answer is : √3+√5+√5−√54

\sqrt{3+\sqrt{5}+\sqrt{5-\sqrt{5}}/{4}

\sqrt{3+\sqrt{5}+\sqrt{5+\sqrt{5}}/{4}

\sqrt{3-\sqrt{5}+\sqrt{5-\sqrt{5}}/{4}

\sqrt{3+\sqrt{5}-\sqrt{5-\sqrt{5}}/{4}

UPSC NDA 2 2016 Mathematics Solved Paper

Question : 48 of 120

Marks: +1, -0

If sin‌180=‌‌

√5−1

, then what is the value of sin‌81°

[NDA II 2016]

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