UPSC CDS Math HCF and LCM of Numbers and Polynomials Questions

Since the HCF of given numbers is the highest common factor of numbers, therefore, numbers are 16a and 16b, where a and b are some natural numbers
16a×16b=7168⇒ab=28.
Here, a and b are co–prime to each other.
Also, 16a > 60, i.e., a > 3 and 16b > 60, i.e., b > 3.
Therefore, the only possible pair for (a, b) can be (4, 7).
Numbers are 16×4, i.e., 64 and 16×7, i.e., 112.
Sum of numbers =64+112=176