UPSC CDS Math Circle Questions

Remember :The perpendicular drawn from the centre of the circle to the chord bisects the chord.
Now, OE ⊥ A
⇒AE=BE=

AB

2

=

5

2

cm
Also,OD ⊥ CD
⇒CF=DF=

CD

2

=6cm
OA=OC=

13

2

cm(Radius of the circle)
In right ΔOCF,OF=√OC2−CF2

In right ΔOAE
=√

144

4

=6cm
Therefore, distance between the chords