If m 2 (sin θ−1) + n 2 (sin θ + 1)=0 , where 0 < θ < \frac{\pi }{2}, then what is (m 2 + n 2 ) cosθ−(m 2 − n 2 ) cot θ equal to?

UPSC CDS I 2025 Mathematics Paper

Question : 30 of 100

Marks: +1, -0

If m²(sin θ−1) + n²(sin θ + 1)=0 , where 0 < θ < ‌

, then what is (m²+ n²) cosθ−(m²− n²) cot θ equal to?

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