UPSC CDS 2 2022 Math Paper

According to the question;
The first train starts from station X at 6 a.m.
6 a.m. to 8 p.m. =8 hours
Distance travelled by X in 8 hour
⇒(60×8)=480‌km
Remaining distance =(1320−480)=840‌km
Now, X & Y travel toward each other
⇒ Relative Speed =60+80=140‌km∕hr
The time is the same at station X and station Y i.e. 2 p.m.
Time when both trains will meet
⇒t=(‌

840

140

)=6 hours
∴ They meet at (2 p.m. +6 p.m.) =8 p.m.