Given product : 150×249×348×...×501 We know one zero is created by multiplication of 2 and 5 i.e., one pair of 2 and 5 in multiplication gives one zero. In the given multiplication, we will find (2×5)n. Here, n represents the number of zeros in the expression. We know that, power of 2 will be more than power of 5 . Hence, we will find (2×5)n with the help of 5n only. Because all 5 , n number of times will be paired with 2 . ∴ Number of 5 in product =546×‌541×536×531×(52)26 ‌×521×516×511×56×(52)1 =‌‌546+41+36+31+52+21+16+11+6+2 =‌‌5262=5n ‌n=262 Hence, there will be 262 zeros in the given product.