UPSC CDS 2 2019 Math Paper

We know that the common triplet sides of a right triangle
(a,‌

a2−1

2

,‌

a2+1

2

)
So here we have one side is 15cm.
‌

152−1

2

=112
Then other side is 2
‌

152+1

2

=113
And third side is 2
Then maximum perimeter =15+112+113=240cm