UPSC CDS 2 2018 Math Paper

Let the perimeter of each figure be 44 cm.
For radius of circle:2×

22

7

×r=44⇒r=7cm
Area of circle =

22

7

×72=154cm2
Side of square =

44

4

=11cm
Area of square =112=121cm2
Side of equilateral triangle =

44

3

cm
Area of equilateral triangle =

√3

4

(

44

3

)2‌~‌93cm2
Therefore, for the same perimeter:Area of equilateral triangle < Area of square < Area of circle
T < S < C