UPSC CDS 2 2018 Math Paper

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Question : 25 of 100

Marks: +1, -0

If ab+bc+ca=0, then the value of

(b2−ca)(c2−ab)+(a2−bc)(c2−ab)+(a2−bc)(b2−ca)

(a2−bc)(b2−ca)(c2−ab)

is

[2018 CDS-II]

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