The position vector of a particle is r^{\to} = 2 t^2x^{\^} + 3ty^{\^} + 4z^{\^} Then the instantaneous velocity v and acceleration a respectively lie [2018 CDS-II]

Correct Answer is : on xy-plane and along x-direction

on xy-plane and along z-direction

on yz-plane and along x-direction

on yz-plane and along ^-direction

on xy-plane and along x-direction

UPSC CDS 2 2018 GK Paper

Question : 9 of 120

Marks: +1, -0

The position vector of a particle is

→

= 2 t2

+ 3t

+ 4

Then the instantaneous velocity v and acceleration a respectively lie

[2018 CDS-II]

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