UPSC CAPF AC 2021 Paper

Radius of small ball, r = 1 cm
Let the radius of big ball be R cm
According to the question,
Volume of big ball = 8 × volume of small ball
⇒

4

3

πR3=8×

4

3

πr3
⇒ R3 = 8 × (1)3 ⇒ R3 = 8
⇒ R = 2
∴ Diameter of new ball = 2R = 2 × 2 = 4 cm