UPSC CAPF AC 2020 Paper

Cost of 20 decigram of gold = ₹ 1000
According to the question,
Cost α (weight) ‌3Cost = K (weight)3 [ ∵ k = a constant]
∴ 1000 = K (20)3
K =

1000

8000

=

1

8

Now, on breaking 20 decigram of gold in ratio 2 : 3, the weight of two pieces is 8 decigram and 12 decigram.
Cost of both the pieces =

1

8

× (8)3 +

1

8

× (12)3
= 64 + 216 = ₹280
Hence, required loss = CP - SP = 1000 - 280
= ₹720