UPSC CAPF AC 2017 Paper

We know that if the length of a rectangle is increased by x%, then to maintain the same area width have to decreased by (

100×x

100+x

)% Here, x=60%
∴ Required decrement in width of rectangle = (

100×x

100+x

)%=(

100×60

100+60

)

100×60

160

=

75

2

=37.5%