UPSC 2017 CDS II Math Paper

Let the time taken by A to finish the race be t seconds.
∴(6×

5

18

)t=100
(1km/hr=

5

18

)

m

s

Time taken by B to finish the race = 60 + 9 = 69 seconds
Distance covered by B = 100 – 8 = 92 m
Therefore, speed of B
=

92

69

m/s
=

92

69

×

18

5

=4.8km/hr