UPSC 2017 CDS I Math Paper

Area of the field = Area of ΔABC + Area of ΔCDH + Area of rectangle AHDG + Area of trapezium DEFG
Now, AC = AH + HC = 3 + 1 = 4 m
Therefore, area of ΔABC
Area of ΔCDH
Area of rectangle AHDG
=HD×DG=2×1=2,m2
Area of trapezium DEFG
=

1

2

×(DG×EF)×GF
=

1

2

×4×2=4m2
Therefore, area of the field
=

3

4

√15+3+2+4
=(9+

3

4

√15)m