UPSC 2017 CDS I Math Paper

Radius of each circle = 3.5 cm
Now, AB = BC = CA = 7 cm
∴ ΔABC is an equilateral triangle.
Area subtended between the circles = Area of the shaded region
= Area of ΔABC – 3 × Area of each sector with θ = 60° and r = 3.5 cm
=‌‌

49√3

4

−‌‌

49

8

π
=‌‌

49

8

(2√3−π)cm2