UPSC 2016 CDS II Math Paper

Let the radius and height of the right circular cylinder be 2k cm and 3k cm, respectively.
∴πr2h=1617cm2
⇒

22

7

×4k2×3k=1617
⇒k3=

1617×7

22×12

=(

7

2

)2
⇒k=

7

2

Radius of the cylinder = 7 cm
Height of the cylinder =

21

2

cm
∴Total surface area of the cylinder =770cm2