UPSC 2015 CDS I Math Paper

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Question : 63 of 100

Marks: +1, -0

If

3−tan2A

1−3tan2A

=K where k is a real number, then cosecA(3sinA−4sin3A) is equal to

[2015 CDS-I]

2K
K−1
2K
K−1
, where
1
3
≤K≤3
2K
K−1
, where K<
1
3
or K>3
2K
K+1

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