UPSC 2014 CDS I Math Paper

In right ΔABC,AC=√AB2+BC2
=√62+82=10cm
Remember: :
In a right triangle, the hypotenuse is a diameter of the circumcircle, and its centre is the mid-point of the hypotenuse
Therefore, length of the circumradius of the Δ‌ABC=

AC

2

=

10

2

=5cm