x3+6x2+11x+6 =x3+x2+5x2+5x+6x+6 =x2(x+1)+5x(x+1)+6(x+1) =(x+1)(x2+5x+6) =(x+1)(x+2)(x+3) So,x3+6x2+11x+6 is divisible by (x+1)(x+2) and (x+3) Hit and Trial Method: Option (a): Putting x=–1 in the given expression, we have (−1)3+6(−1)2+11(−1)+6=0 ⇒(x+1) is factor Option (b): Putting x=–2 in the given expression, we have (−2)3+6(−2)2+11(−2)+6=0 ⇒(x+2) is factor. Similarly, wecan see option (c) is a factor.