UP Police Constable Exam Model Paper 5

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Question : 78 of 150

Marks: +1, -0

What is the value of

(4+18 × 9 ÷ 6-12) /(18 × 15 ÷ 6+23-11) ?

$1 / 5$
$26 / 77$
$23 / 66$
$1 / 3$

Solution:

Given:

(4+18 × 9 ÷ 6-12) /(18 × 15 ÷ 6+23-11)

Concept Used:

B	Brackets in order ( ), { }, [ ]	ब्रेकेट $(),\{\},[]$ क्रम में
O	of	का
D	Division $(÷)$	विभाजन $(÷)$
M	Multiplication $(×)$	गुणा $(×)$
A	Addition $(+)$	जोड़ $(+)$
S/td>	Subtraction $(-)$	घटाव $(-)$

Calculation:

(4+18 × 9 ÷ 6-12) /(18 × 15 ÷ 6+23-11)

⇒(4+18 × 3 / 2-12)/(18 × 5/2+23-11)

⇒(4+27-12) /(45+23-11)

⇒ 19/57=1 / 3

∴

The value of

(4+18 × 9 ÷ 6-12) /(18 × 15 ÷ 6+23-11)

is

1/3

.

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