UP Police Constable Exam Model Paper 2

Given:
Depth of the well = 80 m
In each jump, the frog covered 1.15 m but slipped down by 0.75 m
Calculation:
Net distance covered by the frog in one jump = 1.15 – 0.75 = 0.4 m
So, total number of jumps = 80/0.4 = 200
But here, after 198 jumps, the distance covered = 0.4 × 198 = 79.2 meters
After the 199${}^{\mathrm{th}}$ jump, the distance covered = 79.2 + 1.15 = 80.35 meters
Also, the length of the well = 80 meters.
∴ After the 199${}^{\mathrm{th}}$ jump, the frog would be out of the well