UGC NET Paper 1 GA 5 Jan 2022 Shift 2 Paper

Question : 17 of 50

Marks: +1, -0

The number which is nearest to 3105 and exactly divisible by 21 is :

Solution:

On dividing 3105 by 21 , we get, remainder

=18

Now, number to be added to

3105=21-18=3

Hence, required number

=3105+3=3108

Go to Question:

Prev Question

Next Question