UGC NET Paper 1 GA 2014 June Solved Paper

Question : 11 of 60

Marks: +1, -0

A man started walking from his house towards south. After walking 6 km, he turned to his left and walked 5 km. Then he walked further 3 km after turning left. He then turned to his left and continued his walk for 9 km. How far is he away from his house ?

3 km
4 km
5 km
6 km

Validate

Solution:

BC = DE = 5 km
And DF = 9 km
∴ EF = DF – DE
⇒ EF = 9 – 5 = 4 km
Again AB = 6 km
And CD = BE = 3 km
∴ AE = AB – BE
= 6 – 3 = 3 km
Now in D AEF, AF

=√{(\EF)^2+(\AE)^2}

=√{(4)^2+(3)^2}

=5\Km

Go to Question:

Prev Question

Next Question