TS PSC Group 1 Services Prelims 2019 Paper

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Question : 163 of 200

Marks: +1, -0

Simplify \frac{{{x^2} - 25}}{{x + 3}} \div \frac{{{{(x + 5)}^2}}}{{{x^2} - 9}}

\frac{{(x - 5)(x + 3)}}{{(x - 3)}}
\frac{{(x - 5)(x - 3)}}{{(x + 5)}}
\frac{{(x + 5)(x - 3)}}{{(x + 3)}}
\frac{{(x + 5)(x + 3)}}{{(x - 5)}}

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