\cos\theta=\frac{2x}{1+x^2},\tan\theta=?

TS Police Constable Telugu Model Paper 4

Question : 69 of 200

Marks: +1, -0

cosθ={2x}/{1+x^2},tanθ=?

Solution:

cosθ={2x}/{1+x^2} ={ఆ. భు}/{కర్ణము}

ఎ. భు

=√{(1+x^2)^2-(2x)^2}=√{(1-x)^2}=1-x^2

∴tanθ={ఎ. భు}/{ఆ. భు}={1-x^2}/{2x}

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