TS ICET 30 Sep 2020 Shift 2 Paper

Initially Mandeep is at place $\mathit{X}$ and Sandeep is at place $\mathit{Y}$ and these two places are separated by a distance of $825\mathit{k}\mathit{m}\mathit{s}$. Mandeep started his journey at $35\mathit{k}\mathit{h}\mathit{p}\mathit{h}$ for 3 hours earlier than Sandeep to meet each other. If the speed of Sandeep is $45\mathit{k}\mathit{m}\mathit{p}\mathit{h}$ and they met at place $\mathit{Z}$ between $\mathit{X}$ and $\mathit{Y}$; the distance between $\mathit{Y}$ and $\mathit{Z}$ (in $\mathit{k}\mathit{m}\mathit{s}$ ) is