\sec \\theta+\tan \\theta=

Correct Answer is : 1secθ−tanθ

\frac{1}{\sec \\theta-\tan \\theta}

\frac{1}{\sec \\theta+\tan \\theta}

TS ICET 30 Sep 2020 Shift 2 Paper

Question : 118 of 200

Marks: +1, -0

\sec \θ+\tan \θ=

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