In the figure \\angleA=60^\circ, {BD} \\perp{AC}, and the area of \\DeltaA D C={3 \\sqrt{3}/{2}. Then {BC}=

TS ICET 30 Sep 2020 Shift 1 Paper

Question : 136 of 200

Marks: +1, -0

In the figure

\∠A=60°, {BD} \⊥{AC}

, and the area of

\ΔA D C={3 \√{3}}/{2}

. Then

{BC}=

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