\frac{\cos 690^^\circ+\cot 210^^\circ+\cos \quad 420^^\circ}{\sin 690^^\circ+\sec 210^^\circ+\tan 420^^\circ}=

TS ICET 28-July-2022 Shift-2 Solved Paper

Question : 122 of 200

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{\cos 690^°+\cot 210^°+\cos \quad 420^°}/{\sin 690^°+\sec 210^°+\tan 420^°}=

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