\sec \theta+\tan \theta=k \Rightarrow \frac{k^2+1}{k^2-1}=

TS ICET 27 May 2023 Shift 2 Solved Paper

Question : 125 of 200

Marks: +1, -0

\sec θ+\tan θ=k ⇒ \;{k^2+1}/{k^2-1}=

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