TS ICET 27-July-2022 Shift-2 Solved Paper

In a certain code, ${\mathrm{n}}^{\mathrm{th}}$ letter in the English alphabet is coded as $\left(\mathrm{n}+4\right){\left(\mathrm{mod}26\right)}^{\mathrm{th}}$ letter if n is even and $\left(\mathrm{n}-4\right){\left(\mathrm{b}\mathrm{mod}26\right)}^{\mathrm{th}}$ letter if n is odd. The inverse process is used for decoding.
Using this information answer the questions from 56 to 60 .