tan 20^^\circ = \x \Rightarrow \frac{\tan 250^^\circ + \tan 340^^\circ}{\tan 200^^\circ - \tan 110^^\circ} =

TS ICET 27-July-2022 Shift-1 Solved Paper

Question : 123 of 200

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tan

20^° = \x ⇒ {\tan 250^° + \tan 340^°}/{\tan 200^° - \tan 110^°}

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