If 27 \x^3-54 \x^2+36 \x-8=0, then (\x^2 + 1/\x^2) + 4 (\x + 1/\x) + 3 =

TS ICET 27-July-2022 Shift-1 Solved Paper

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27 \x^3-54 \x^2+36 \x-8=0

, then

(\x^2 + 1/\x^2) + 4 (\x + 1/\x)

+ 3 =

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