TS ICET 24 May 2019 Shift 1 Paper

Question : 80 of 200

Marks: +1, -0

x =

5 + ∛5 + ∛{25}

⇒

x^3-15x^2+60x+10

Solution:

x=5+√^3{5}+√^3{25}

x-5=5^{\;{1}/{3}}+5^{\;{2}/{3}}

(x-5)=(5^{\;{1}/{3}}+5^{\;{2}/{3}})^{3}

x^{3}-15 x^{2}+75 x-125=5+5^{2}+3.5(x-5)

x^{3}-15 x^{2}+75 x-15 x=5+25-75+125

x^{3}-15 x^{2}+60 x=80

x^{3}-15 x^{2}+60 x+10=80+10=90

Go to Question:

Prev Question

Next Question