TS ICET 24 May 2019 Shift 1 Paper

Question : 78 of 200

Marks: +1, -0

ab : bc : ca = 3:1:2 ⇒

a/{bc} : b/{ca}

Solution:

ab : bc : ca = 3 : 1 : 2

\;{1}/{c}: \;{1}/{a}: \;{1}/{b}=3: 1: 2

c: a: b=\;{1}/{3}: 1: \;{1}/{2}

c: a: b=2: 6: 3

a: b: c=6: 3: 2

\;{a}/{b c}: \;{b}/{c a} ⇒ \;{6 k}/{3 k ⋅ 2 K}: \;{3 k}/{6 k ⋅ 2 k}

=1: \;{1}/{4}=4: 1

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