\frac{(x+1/y)^a . (x-1/y)^b}{(y+1/x)^a . (y-1/x)^b} =

TS ICET 24 May 2019 Shift 1 Paper

Question : 76 of 200

Marks: +1, -0

{(x+1/y)^a . (x-1/y)^b}/{(y+1/x)^a . (y-1/x)^b}

Solution:

\;{(x+{1}/{y})^{a}(x-{1}/{y})^{b}}/{(y+\;{1}/{x})^{a}(y-\;{1}/{x})^{b}}=\;{\;{(x y+1)^{a}}/{y^{a}} {(x y-1)^{b}}/{y^{b}}}/{{(x y+1)^{a}}/{x^{a}} \;{(x y-1)^{b}}/{x^{b}}} ⇒

=\;{x^{a} x^{b}}/{y^{a} y^{b}}=(\;{x}/{y})^{a+b}

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