For the ten observations x_1,x_2 , ... , x_{10} it is given that \sum^{10}_{i=1} x_i = 12 and \sum^{10}_{i=1} x_i^2 = 18. Then the standard deviation of the data is:

TS ICET 24 May 2019 Shift 1 Paper

Question : 145 of 200

Marks: +1, -0

For the ten observations

x_1,x_2

, ... ,

x_{10}

it is given that

Σ↖{10}↙{i=1} x_i

= 12 and

Σ↖{10}↙{i=1} x_i^2

= 18. Then the standard deviation of the data is:

Solution:

=√{\;{∑ x_{i}^{2}}/{n}-(\;{∑ x_{i}}/{n})^{2}}

=√{\;{18}/{10}-(\;{12}/{10})^{2}}

=√{\;{9}/{5}-\;{36}/{25}}=√{\;{45-36}/{25}}=√{\;{9}/{25}}

=3/5

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