\lim_{x\to0} {sinx-x}/x^3

TS ICET 24 May 2019 Shift 1 Paper

Question : 134 of 200

Marks: +1, -0

\lim↙{x→0} {sinx-x}/x^3

Solution:

\lim ↙{x → 0} \;{\sinx-x}/{x^{3}}

\lim ↙{x → 0} \;{\cos x-1}/{3 x^{2}}

(By L Hospital rule)

⇒ \lim ↙{x → 0} \;{-\sin x}/{6 x}

L Hospital rule

⇒ \;{-1}/{6}

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