A + B = \pi/4 ⇒ (1 + tan A) (1 + tan B) =

TS ICET 24 May 2019 Shift 1 Paper

Question : 120 of 200

Marks: +1, -0

A + B =

π/4

⇒ (1 + tan A) (1 + tan B) =

Solution:

A+B=\;{π}/{4}

\tan (A+B)=\tan \;{π}/{4}

\;{\tan A+\tan B}/{1-\tan A \tan B}=1

\tan A+\tan B=1-\tan A \tan B

\tan A+\tan B+\tan A \tan B=1

Now,

(1+\tan A)(1+\tan B)

=1+\tan A+\tan B+\tan A \tan B

=1+1=2

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