TS ICET 24 May 2018 Shift 1 Paper

Question : 143 of 200

Marks: +1, -0

\m_1.\m_2 \and \m_3

respectively denote the arithmetic mean, median and mode of a distribution then

Solution:

Mode = 3 median – 2 mean.
Mode – mean = 3 median – 3 mean

m_3 – m_1 = 3(m_2–m_1)

⇒ m _{1}- m _{3}=3( m _{1}- m _{2})

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