TS ICET 23 May 2019 Shift 2 Paper

Question : 83 of 200

Marks: +1, -0

The numbers of divisors of 1248 other than 1 and the number itself is:

Solution:

1248=2^{5} x 3^{1} × 13^{1}

Hence the number of factors of 1248

= (5 + 1)(1 + 1)(1 + 1)

i.e. 24
But excluding 1 and 1248, the remaining number of factors is 22.

Go to Question:

Prev Question

Next Question