TS ICET 23 May 2019 Shift 2 Paper

Question : 76 of 200

Marks: +1, -0

x^y

y^x

⇒

(x/y)^{y/x}

Solution:

x^{y}=y^{x}, y=x^{\;{y}/{x}}

(\;{x}/{y})^{\;{y}/{x}}=\;{x^{{y}/{x}}}/{y^{'}}=\;{y}/{y^{'}}=y^{1-\;{y}/{x}}

Go to Question:

Prev Question

Next Question