TS ICET 23 May 2019 Shift 2 Paper

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Question : 147 of 200

Marks: +1, -0

If A and B are two events in a random experiment with the probabilities P (A) =

3/8

, P (B) =

1/3

and P (A ∩ B) =

1/4

, then P

(A↖{-}∩B↖{-})

Here,

A↖{-}

is the complementary event

13/24
11/24
7/24
5/24

Solution:

P(\ov{A} ∩ \ov{B})=P(\ov{A ∪ B})=1-P(A∪B)

1-[P(A)+P(B)-P(A ∩ B)]

1-[\;{3}/{8}+\;{1}/{3}-\;{1}/{4}]=\;{13}/{24}

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