TS ICET 23 May 2019 Shift 2 Paper

Question : 125 of 200

Marks: +1, -0

The remainder when

x^4+4x^3-5x^2-6x+7

is divided by x - 3, is

Solution:

Let

x^4+4x^3-5x^2-6x+7

The remainder is

f(3)=3^{4}+4(3)^{3}-5(3)^{2}-6(3)+7=133

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