TS ICET 23 May 2019 Shift 1 Paper

Question : 76 of 200

Marks: +1, -0

If a =

2^x

, b =

4^y

, c =

8^z

and

a^{yz} .b^{zx}. c^{xy}

4^6

, then xyz =__________

Solution:

a=2^{x} ⇒ a^{y z}=(2^{x})^{y z}=2^{x y z}

b=4^{y} ⇒ b^{x z}=(4 y)^{x z}=4^{x y z}

c=8^{2} ⇒ c^{x y}=(8^{2})^{x y}=8^{x y z}

Given

\left.a^{y z}) ⋅(b^{z x}) ⋅(c^{x y})=4^{6}

⇒(2^{x y z}) ⋅(4^{x y z}) ⋅(8^{x y z})=4^{6}

⇒ 64^{x y z}=4^{6}=(4^{3})^{2}=64^{2}

⇒ x y z=2

Go to Question:

Prev Question

Next Question