TS ICET 23 May 2019 Shift 1 Paper

For this question, discrepancy is found in question/answer. Full Marks is being awarded to all candidates.
Question wrong :
Given question is $1,2,\frac{27}{8},4,\frac{125}{32}$
In the above series instead of 1 it should be given as $\frac{1}{2}$
Then the new series is as follows.
$\frac{1}{2},2,\frac{27}{8},4,\frac{125}{32}$
Logic is,$\frac{1^3}{2},\frac{2^3}{4},\frac{3^3}{8},\frac{4^3}{16},\frac{5^3}{32},\frac{6^3}{64}=\frac{27}{8}$